5p(p-2)=2

Solution for 5p(p-2)=2 equation:

5p(p-2)=2

We move all terms to the left:

5p(p-2)-(2)=0

We multiply parentheses

5p^2-10p-2=0

a = 5; b = -10; c = -2;
Δ = b2-4ac
Δ = -102-4·5·(-2)
Δ = 140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{140}=\sqrt{4*35}=\sqrt{4}*\sqrt{35}=2\sqrt{35}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{35}}{2*5}=\frac{10-2\sqrt{35}}{10}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{35}}{2*5}=\frac{10+2\sqrt{35}}{10}
$