5p+1/5(40-p)=0

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Solution for 5p+1/5(40-p)=0 equation: 



5p+1/5(40-p)=0



Domain of the equation: 5(40-p)!=0

p∈R



We add all the numbers together, and all the variables

5p+1/5(-1p+40)=0

We multiply all the terms by the denominator


5p*5(-1p+40)+1=0

Wy multiply elements

25p^2(-+1=0

We use the square of the difference formula

25p^2(-1=0

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