5p+3/5(2p+5)+23=5p+(3p-2)+21

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Solution for 5p+3/5(2p+5)+23=5p+(3p-2)+21 equation: 



5p+3/5(2p+5)+23=5p+(3p-2)+21

We move all terms to the left:

5p+3/5(2p+5)+23-(5p+(3p-2)+21)=0



Domain of the equation: 5(2p+5)!=0

p∈R



We multiply all the terms by the denominator


5p*5(2p+5)-((5p+(3p-2)+21))*5(2p+5)+23*5(2p+5)+3=0



We calculate terms in parentheses: -((5p+(3p-2)+21))*5(2p+5), so:

(5p+(3p-2)+21))*5(2p+5



Wy multiply elements

25p^2(2-((5p+(3p-2)+21))*5(2p+5)+115p(2+3=0

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