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5p+4(p-1)=2+5(2+p)
We move all terms to the left:
5p+4(p-1)-(2+5(2+p))=0
We add all the numbers together, and all the variables
5p+4(p-1)-(2+5(p+2))=0
We multiply parentheses
5p+4p-(2+5(p+2))-4=0
We calculate terms in parentheses: -(2+5(p+2)), so:We add all the numbers together, and all the variables
2+5(p+2)
determiningTheFunctionDomain 5(p+2)+2
We multiply parentheses
5p+10+2
We add all the numbers together, and all the variables
5p+12
Back to the equation:
-(5p+12)
9p-(5p+12)-4=0
We get rid of parentheses
9p-5p-12-4=0
We add all the numbers together, and all the variables
4p-16=0
We move all terms containing p to the left, all other terms to the right
4p=16
p=16/4
p=4
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