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5p-8/3p+9=7
We move all terms to the left:
5p-8/3p+9-(7)=0
Domain of the equation: 3p!=0We add all the numbers together, and all the variables
p!=0/3
p!=0
p∈R
5p-8/3p+2=0
We multiply all the terms by the denominator
5p*3p+2*3p-8=0
Wy multiply elements
15p^2+6p-8=0
a = 15; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·15·(-8)
Δ = 516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{516}=\sqrt{4*129}=\sqrt{4}*\sqrt{129}=2\sqrt{129}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{129}}{2*15}=\frac{-6-2\sqrt{129}}{30} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{129}}{2*15}=\frac{-6+2\sqrt{129}}{30} $
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