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5p^2+22p+8=0
a = 5; b = 22; c = +8;
Δ = b2-4ac
Δ = 222-4·5·8
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-18}{2*5}=\frac{-40}{10} =-4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+18}{2*5}=\frac{-4}{10} =-2/5 $
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