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5p^2-5=2p
We move all terms to the left:
5p^2-5-(2p)=0
a = 5; b = -2; c = -5;
Δ = b2-4ac
Δ = -22-4·5·(-5)
Δ = 104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{104}=\sqrt{4*26}=\sqrt{4}*\sqrt{26}=2\sqrt{26}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{26}}{2*5}=\frac{2-2\sqrt{26}}{10} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{26}}{2*5}=\frac{2+2\sqrt{26}}{10} $
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