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5p^2=315
We move all terms to the left:
5p^2-(315)=0
a = 5; b = 0; c = -315;
Δ = b2-4ac
Δ = 02-4·5·(-315)
Δ = 6300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6300}=\sqrt{900*7}=\sqrt{900}*\sqrt{7}=30\sqrt{7}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{7}}{2*5}=\frac{0-30\sqrt{7}}{10} =-\frac{30\sqrt{7}}{10} =-3\sqrt{7} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{7}}{2*5}=\frac{0+30\sqrt{7}}{10} =\frac{30\sqrt{7}}{10} =3\sqrt{7} $
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