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5p=4(1/2p-1)
We move all terms to the left:
5p-(4(1/2p-1))=0
Domain of the equation: 2p-1))!=0We multiply all the terms by the denominator
p∈R
5p*2p-1))-(4(1=0
We add all the numbers together, and all the variables
5p*2p=0
Wy multiply elements
10p^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$p=\frac{-b}{2a}=\frac{0}{20}=0$
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