5q+(1-q)=8q+2(1-q)

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Solution for 5q+(1-q)=8q+2(1-q) equation: 



5q+(1-q)=8q+2(1-q)

We move all terms to the left:

5q+(1-q)-(8q+2(1-q))=0

We add all the numbers together, and all the variables

5q+(-1q+1)-(8q+2(-1q+1))=0

We get rid of parentheses

5q-1q-(8q+2(-1q+1))+1=0



We calculate terms in parentheses: -(8q+2(-1q+1)), so:

8q+2(-1q+1)

We multiply parentheses

8q-2q+2

We add all the numbers together, and all the variables

6q+2

Back to the equation:

-(6q+2)



We add all the numbers together, and all the variables

4q-(6q+2)+1=0

We get rid of parentheses

4q-6q-2+1=0

We add all the numbers together, and all the variables

-2q-1=0

We move all terms containing q to the left, all other terms to the right

-2q=1

q=1/-2

q=-1/2

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