5q+6(1-q)=6q+4(1-q)

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Solution for 5q+6(1-q)=6q+4(1-q) equation: 



5q+6(1-q)=6q+4(1-q)

We move all terms to the left:

5q+6(1-q)-(6q+4(1-q))=0

We add all the numbers together, and all the variables

5q+6(-1q+1)-(6q+4(-1q+1))=0

We multiply parentheses

5q-6q-(6q+4(-1q+1))+6=0



We calculate terms in parentheses: -(6q+4(-1q+1)), so:

6q+4(-1q+1)

We multiply parentheses

6q-4q+4

We add all the numbers together, and all the variables

2q+4

Back to the equation:

-(2q+4)



We add all the numbers together, and all the variables

-1q-(2q+4)+6=0

We get rid of parentheses

-1q-2q-4+6=0

We add all the numbers together, and all the variables

-3q+2=0

We move all terms containing q to the left, all other terms to the right

-3q=-2

q=-2/-3

q=2/3

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