5q-(9q+3)=7-(14q-9)

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Solution for 5q-(9q+3)=7-(14q-9) equation: 



5q-(9q+3)=7-(14q-9)

We move all terms to the left:

5q-(9q+3)-(7-(14q-9))=0

We get rid of parentheses

5q-9q-(7-(14q-9))-3=0



We calculate terms in parentheses: -(7-(14q-9)), so:

7-(14q-9)

determiningTheFunctionDomain
-(14q-9)+7

We get rid of parentheses

-14q+9+7

We add all the numbers together, and all the variables

-14q+16

Back to the equation:

-(-14q+16)



We add all the numbers together, and all the variables

-4q-(-14q+16)-3=0

We get rid of parentheses

-4q+14q-16-3=0

We add all the numbers together, and all the variables

10q-19=0

We move all terms containing q to the left, all other terms to the right

10q=19

q=19/10

q=1+9/10

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