5q-3(q-2)=-5(3-2q)+5

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Solution for 5q-3(q-2)=-5(3-2q)+5 equation: 



5q-3(q-2)=-5(3-2q)+5

We move all terms to the left:

5q-3(q-2)-(-5(3-2q)+5)=0

We add all the numbers together, and all the variables

5q-3(q-2)-(-5(-2q+3)+5)=0

We multiply parentheses

5q-3q-(-5(-2q+3)+5)+6=0



We calculate terms in parentheses: -(-5(-2q+3)+5), so:

-5(-2q+3)+5

We multiply parentheses

10q-15+5

We add all the numbers together, and all the variables

10q-10

Back to the equation:

-(10q-10)



We add all the numbers together, and all the variables

2q-(10q-10)+6=0

We get rid of parentheses

2q-10q+10+6=0

We add all the numbers together, and all the variables

-8q+16=0

We move all terms containing q to the left, all other terms to the right

-8q=-16

q=-16/-8

q=+2

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