5q-7=a2/3

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Solution for 5q-7=a2/3 equation: 


x in (-oo:+oo)

5*q-7 = (a^2)/3 // - (a^2)/3

5*q-((a^2)/3)-7 = 0

5*q-1/3*a^2-7 = 0

x należy do R

x in (-oo:+oo)

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