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5q^2=7q
We move all terms to the left:
5q^2-(7q)=0
a = 5; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·5·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*5}=\frac{0}{10} =0 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*5}=\frac{14}{10} =1+2/5 $
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