5q=4-3(2q-6)

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Solution for 5q=4-3(2q-6) equation: 



5q=4-3(2q-6)

We move all terms to the left:

5q-(4-3(2q-6))=0



We calculate terms in parentheses: -(4-3(2q-6)), so:

4-3(2q-6)

determiningTheFunctionDomain
-3(2q-6)+4

We multiply parentheses

-6q+18+4

We add all the numbers together, and all the variables

-6q+22

Back to the equation:

-(-6q+22)



We get rid of parentheses

5q+6q-22=0

We add all the numbers together, and all the variables

11q-22=0

We move all terms containing q to the left, all other terms to the right

11q=22

q=22/11

q=2

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