5r(-2)r=-3

Solution for 5r(-2)r=-3 equation:

5r(-2)r=-3

We move all terms to the left:

5r(-2)r-(-3)=0

We add all the numbers together, and all the variables

5r(-2)r+3=0

We multiply parentheses

-10r^2+3=0

a = -10; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-10)·3
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{30}}{2*-10}=\frac{0-2\sqrt{30}}{-20}
=-\frac{2\sqrt{30}}{-20}
=-\frac{\sqrt{30}}{-10}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{30}}{2*-10}=\frac{0+2\sqrt{30}}{-20}
=\frac{2\sqrt{30}}{-20}
=\frac{\sqrt{30}}{-10}
$