5r+(r-6)+(3r-3)=180

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Solution for 5r+(r-6)+(3r-3)=180 equation:



5r+(r-6)+(3r-3)=180
We move all terms to the left:
5r+(r-6)+(3r-3)-(180)=0
We get rid of parentheses
5r+r+3r-6-3-180=0
We add all the numbers together, and all the variables
9r-189=0
We move all terms containing r to the left, all other terms to the right
9r=189
r=189/9
r=21

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