5r-6(7+2r)=6-(r-5)

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Solution for 5r-6(7+2r)=6-(r-5) equation: 



5r-6(7+2r)=6-(r-5)

We move all terms to the left:

5r-6(7+2r)-(6-(r-5))=0

We add all the numbers together, and all the variables

5r-6(2r+7)-(6-(r-5))=0

We multiply parentheses

5r-12r-(6-(r-5))-42=0



We calculate terms in parentheses: -(6-(r-5)), so:

6-(r-5)

determiningTheFunctionDomain
-(r-5)+6

We get rid of parentheses

-r+5+6

We add all the numbers together, and all the variables

-1r+11

Back to the equation:

-(-1r+11)



We add all the numbers together, and all the variables

-7r-(-1r+11)-42=0

We get rid of parentheses

-7r+1r-11-42=0

We add all the numbers together, and all the variables

-6r-53=0

We move all terms containing r to the left, all other terms to the right

-6r=53

r=53/-6

r=-8+5/6

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