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5r^2-7r-6=0
a = 5; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·5·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-13}{2*5}=\frac{-6}{10} =-3/5 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+13}{2*5}=\frac{20}{10} =2 $
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