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5r^2=47.1
We move all terms to the left:
5r^2-(47.1)=0
We add all the numbers together, and all the variables
5r^2-47.1=0
a = 5; b = 0; c = -47.1;
Δ = b2-4ac
Δ = 02-4·5·(-47.1)
Δ = 942
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{942}}{2*5}=\frac{0-\sqrt{942}}{10} =-\frac{\sqrt{}}{10} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{942}}{2*5}=\frac{0+\sqrt{942}}{10} =\frac{\sqrt{}}{10} $
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