5r=3(r+3)-7

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Solution for 5r=3(r+3)-7 equation: 



5r=3(r+3)-7

We move all terms to the left:

5r-(3(r+3)-7)=0



We calculate terms in parentheses: -(3(r+3)-7), so:

3(r+3)-7

We multiply parentheses

3r+9-7

We add all the numbers together, and all the variables

3r+2

Back to the equation:

-(3r+2)



We get rid of parentheses

5r-3r-2=0

We add all the numbers together, and all the variables

2r-2=0

We move all terms containing r to the left, all other terms to the right

2r=2

r=2/2

r=1

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