5t(2t=14)=3t-14

Solution for 5t(2t=14)=3t-14 equation:

5t(2t=14)=3t-14

We move all terms to the left:

5t(2t-(14))=0

We multiply parentheses

10t^2-70t=0

a = 10; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·10·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*10}=\frac{0}{20}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*10}=\frac{140}{20}
=7
$