5t(t-11)=0

Solution for 5t(t-11)=0 equation:

5t(t-11)=0

We multiply parentheses

5t^2-55t=0

a = 5; b = -55; c = 0;
Δ = b2-4ac
Δ = -552-4·5·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-55}{2*5}=\frac{0}{10}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+55}{2*5}=\frac{110}{10}
=11
$