5t+1=3(t-2)

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Solution for 5t+1=3(t-2) equation: 



5t+1=3(t-2)

We move all terms to the left:

5t+1-(3(t-2))=0



We calculate terms in parentheses: -(3(t-2)), so:

3(t-2)

We multiply parentheses

3t-6

Back to the equation:

-(3t-6)



We get rid of parentheses

5t-3t+6+1=0

We add all the numbers together, and all the variables

2t+7=0

We move all terms containing t to the left, all other terms to the right

2t=-7

t=-7/2

t=-3+1/2

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