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5t+2=-1/2t
We move all terms to the left:
5t+2-(-1/2t)=0
Domain of the equation: 2t)!=0We get rid of parentheses
t!=0/1
t!=0
t∈R
5t+1/2t+2=0
We multiply all the terms by the denominator
5t*2t+2*2t+1=0
Wy multiply elements
10t^2+4t+1=0
a = 10; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·10·1
Δ = -24
Delta is less than zero, so there is no solution for the equation
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