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5t+3=-1/2(t+2)
We move all terms to the left:
5t+3-(-1/2(t+2))=0
Domain of the equation: 2(t+2))!=0We multiply all the terms by the denominator
t∈R
5t*2(t+2))-(+3*2(t+2))-1=0
Wy multiply elements
10t^2(t+6t(t=0
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