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5t+3t=5-3(t+5)
We move all terms to the left:
5t+3t-(5-3(t+5))=0
We add all the numbers together, and all the variables
8t-(5-3(t+5))=0
We calculate terms in parentheses: -(5-3(t+5)), so:We get rid of parentheses
5-3(t+5)
determiningTheFunctionDomain -3(t+5)+5
We multiply parentheses
-3t-15+5
We add all the numbers together, and all the variables
-3t-10
Back to the equation:
-(-3t-10)
8t+3t+10=0
We add all the numbers together, and all the variables
11t+10=0
We move all terms containing t to the left, all other terms to the right
11t=-10
t=-10/11
t=-10/11
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