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5t-3t=5-3(t+7)
We move all terms to the left:
5t-3t-(5-3(t+7))=0
We add all the numbers together, and all the variables
2t-(5-3(t+7))=0
We calculate terms in parentheses: -(5-3(t+7)), so:We get rid of parentheses
5-3(t+7)
determiningTheFunctionDomain -3(t+7)+5
We multiply parentheses
-3t-21+5
We add all the numbers together, and all the variables
-3t-16
Back to the equation:
-(-3t-16)
2t+3t+16=0
We add all the numbers together, and all the variables
5t+16=0
We move all terms containing t to the left, all other terms to the right
5t=-16
t=-16/5
t=-3+1/5
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