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5t^2+75t+70=0
a = 5; b = 75; c = +70;
Δ = b2-4ac
Δ = 752-4·5·70
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-65}{2*5}=\frac{-140}{10} =-14 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+65}{2*5}=\frac{-10}{10} =-1 $
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