5t2-15t-50=0

Solution for 5t2-15t-50=0 equation:

5t^2-15t-50=0

a = 5; b = -15; c = -50;
Δ = b2-4ac
Δ = -152-4·5·(-50)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-35}{2*5}=\frac{-20}{10}
=-2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+35}{2*5}=\frac{50}{10}
=5
$