5t2-7t=4

Solution for 5t2-7t=4 equation:

5t^2-7t=4

We move all terms to the left:

5t^2-7t-(4)=0

a = 5; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·5·(-4)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{129}}{2*5}=\frac{7-\sqrt{129}}{10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{129}}{2*5}=\frac{7+\sqrt{129}}{10}
$