5t2-8t-50=0

Solution for 5t2-8t-50=0 equation:

5t^2-8t-50=0

a = 5; b = -8; c = -50;
Δ = b2-4ac
Δ = -82-4·5·(-50)
Δ = 1064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1064}=\sqrt{4*266}=\sqrt{4}*\sqrt{266}=2\sqrt{266}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{266}}{2*5}=\frac{8-2\sqrt{266}}{10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{266}}{2*5}=\frac{8+2\sqrt{266}}{10}
$