5u(u+2)+5=0

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Solution for 5u(u+2)+5=0 equation: 



5u(u+2)+5=0

We multiply parentheses

5u^2+10u+5=0

a = 5; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·5·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{-10}{10}=-1$

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