5u+1-4(-2u-2)=3(u-2)

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Solution for 5u+1-4(-2u-2)=3(u-2) equation:



5u+1-4(-2u-2)=3(u-2)
We move all terms to the left:
5u+1-4(-2u-2)-(3(u-2))=0
We multiply parentheses
5u+8u-(3(u-2))+8+1=0
We calculate terms in parentheses: -(3(u-2)), so:
3(u-2)
We multiply parentheses
3u-6
Back to the equation:
-(3u-6)
We add all the numbers together, and all the variables
13u-(3u-6)+9=0
We get rid of parentheses
13u-3u+6+9=0
We add all the numbers together, and all the variables
10u+15=0
We move all terms containing u to the left, all other terms to the right
10u=-15
u=-15/10
u=-1+1/2

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