If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5u^2+8u+3=0
a = 5; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·5·3
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2}{2*5}=\frac{-10}{10} =-1 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2}{2*5}=\frac{-6}{10} =-3/5 $
| -3(x-2)/5=-1/3+x/6 | | -11x=-7(1-2x)+5 | | 5u2+8u-3=0 | | 9v2+11v+5=4v2 | | 2(n+9)-5n=0 | | 8(m+10)=60-12m | | 2y/2=-4 | | 5u2+8u=3 | | |x–84|=0.5 | | 2x^2+62x=720 | | 13a-7a=24 | | 2.5x+10=x-0.05 | | 3/5x=-96 | | x^2+18x-130=0 | | 4b2-5b-4=0 | | -12(5n+4)=-5n-48 | | 19-9x=-5(x-11) | | 5p=3p-16 | | 5(3x-2)=2(2x+1) | | 10+3x=24-x-3x | | q^2+4q-6=0 | | 3x-0.5=0.7 | | 4x+9=49−6x | | 24-8x=15x | | (2x-3/3)-(x-1/2)=x/3 | | 2x-3/3-x-1/2=x/3 | | -16+11s=s-6+20s | | 7x+14-5x+15=3 | | -2y-11=-y | | −(7x)+5=47 | | 12(x)+8(2.5)=256 | | −7x+5=47 |