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5v(2v-4)=-12
We move all terms to the left:
5v(2v-4)-(-12)=0
We add all the numbers together, and all the variables
5v(2v-4)+12=0
We multiply parentheses
10v^2-20v+12=0
a = 10; b = -20; c = +12;
Δ = b2-4ac
Δ = -202-4·10·12
Δ = -80
Delta is less than zero, so there is no solution for the equation
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