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5v(v+9)=0
We multiply parentheses
5v^2+45v=0
a = 5; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·5·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*5}=\frac{-90}{10} =-9 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*5}=\frac{0}{10} =0 $
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