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5v+1/2=4+3/2v
We move all terms to the left:
5v+1/2-(4+3/2v)=0
Domain of the equation: 2v)!=0We add all the numbers together, and all the variables
v!=0/1
v!=0
v∈R
5v-(3/2v+4)+1/2=0
We get rid of parentheses
5v-3/2v-4+1/2=0
We calculate fractions
5v-4=0
We move all terms containing v to the left, all other terms to the right
5v=4
v=4/5
v=4/5
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