5v+32=2(v+4)

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Solution for 5v+32=2(v+4) equation: 



5v+32=2(v+4)

We move all terms to the left:

5v+32-(2(v+4))=0



We calculate terms in parentheses: -(2(v+4)), so:

2(v+4)

We multiply parentheses

2v+8

Back to the equation:

-(2v+8)



We get rid of parentheses

5v-2v-8+32=0

We add all the numbers together, and all the variables

3v+24=0

We move all terms containing v to the left, all other terms to the right

3v=-24

v=-24/3

v=-8

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