5v+4(-3+v)=6(v+2)

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Solution for 5v+4(-3+v)=6(v+2) equation: 



5v+4(-3+v)=6(v+2)

We move all terms to the left:

5v+4(-3+v)-(6(v+2))=0

We add all the numbers together, and all the variables

5v+4(v-3)-(6(v+2))=0

We multiply parentheses

5v+4v-(6(v+2))-12=0



We calculate terms in parentheses: -(6(v+2)), so:

6(v+2)

We multiply parentheses

6v+12

Back to the equation:

-(6v+12)



We add all the numbers together, and all the variables

9v-(6v+12)-12=0

We get rid of parentheses

9v-6v-12-12=0

We add all the numbers together, and all the variables

3v-24=0

We move all terms containing v to the left, all other terms to the right

3v=24

v=24/3

v=8

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