5v+4-2(-8v-3)=3(v-2)

Solution for 5v+4-2(-8v-3)=3(v-2) equation:

5v+4-2(-8v-3)=3(v-2)

We move all terms to the left:

5v+4-2(-8v-3)-(3(v-2))=0

We multiply parentheses

5v+16v-(3(v-2))+6+4=0


We calculate terms in parentheses: -(3(v-2)), so:

3(v-2)

We multiply parentheses

3v-6

Back to the equation:

-(3v-6)


We add all the numbers together, and all the variables

21v-(3v-6)+10=0

We get rid of parentheses

21v-3v+6+10=0

We add all the numbers together, and all the variables

18v+16=0

We move all terms containing v to the left, all other terms to the right

18v=-16

v=-16/18

v=-8/9