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5v-2=-6v-5(1v-6)
We move all terms to the left:
5v-2-(-6v-5(1v-6))=0
We add all the numbers together, and all the variables
5v-(-6v-5(v-6))-2=0
We calculate terms in parentheses: -(-6v-5(v-6)), so:We get rid of parentheses
-6v-5(v-6)
We multiply parentheses
-6v-5v+30
We add all the numbers together, and all the variables
-11v+30
Back to the equation:
-(-11v+30)
5v+11v-30-2=0
We add all the numbers together, and all the variables
16v-32=0
We move all terms containing v to the left, all other terms to the right
16v=32
v=32/16
v=2
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