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5v-v=2(v+1)
We move all terms to the left:
5v-v-(2(v+1))=0
We add all the numbers together, and all the variables
4v-(2(v+1))=0
We calculate terms in parentheses: -(2(v+1)), so:We get rid of parentheses
2(v+1)
We multiply parentheses
2v+2
Back to the equation:
-(2v+2)
4v-2v-2=0
We add all the numbers together, and all the variables
2v-2=0
We move all terms containing v to the left, all other terms to the right
2v=2
v=2/2
v=1
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