5v2+11v=-6

Solution for 5v2+11v=-6 equation:

5v^2+11v=-6

We move all terms to the left:

5v^2+11v-(-6)=0

We add all the numbers together, and all the variables

5v^2+11v+6=0

a = 5; b = 11; c = +6;
Δ = b2-4ac
Δ = 112-4·5·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-1}{2*5}=\frac{-12}{10}
=-1+1/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+1}{2*5}=\frac{-10}{10}
=-1
$