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5v^2+17v+5=6v
We move all terms to the left:
5v^2+17v+5-(6v)=0
We add all the numbers together, and all the variables
5v^2+11v+5=0
a = 5; b = 11; c = +5;
Δ = b2-4ac
Δ = 112-4·5·5
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{21}}{2*5}=\frac{-11-\sqrt{21}}{10} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{21}}{2*5}=\frac{-11+\sqrt{21}}{10} $
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