5v2+27v=-6

Solution for 5v2+27v=-6 equation:

5v^2+27v=-6

We move all terms to the left:

5v^2+27v-(-6)=0

We add all the numbers together, and all the variables

5v^2+27v+6=0

a = 5; b = 27; c = +6;
Δ = b2-4ac
Δ = 272-4·5·6
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{609}}{2*5}=\frac{-27-\sqrt{609}}{10}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{609}}{2*5}=\frac{-27+\sqrt{609}}{10}
$