5w+2-7w+4(w+3)/2

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Solution for 5w+2-7w+4(w+3)/2 equation: 


w in (-oo:+oo)

(4*(w+3))/2+5*w-(7*w)+2 = 0

(4*(w+3))/2+5*w-7*w+2 = 0

(4*(w+3))/2+(2*5*w)/2+(-7*2*w)/2+(2^2)/2 = 0

4*(w+3)+2*5*w-7*2*w+4 = 0

14*w-14*w+4+12 = 0

4+12 = 0

16 = 0

16/2 = 0

16/2 = 0 // * 2

16 = 0

w belongs to the empty set

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