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5w+8(-w)=6w(-2)(w-4)
We move all terms to the left:
5w+8(-w)-(6w(-2)(w-4))=0
We add all the numbers together, and all the variables
5w+8(-1w)-(6w(-2)(w-4))=0
We multiply parentheses
5w-8w-(6w(-2)(w-4))=0
We multiply parentheses ..
5w-8w-(6w(-2w+8))=0
We calculate terms in parentheses: -(6w(-2w+8)), so:We add all the numbers together, and all the variables
6w(-2w+8)
We multiply parentheses
-12w^2+48w
Back to the equation:
-(-12w^2+48w)
-(-12w^2+48w)-3w=0
We get rid of parentheses
12w^2-48w-3w=0
We add all the numbers together, and all the variables
12w^2-51w=0
a = 12; b = -51; c = 0;
Δ = b2-4ac
Δ = -512-4·12·0
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-51}{2*12}=\frac{0}{24} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+51}{2*12}=\frac{102}{24} =4+1/4 $
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