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5w-51.25=13+3/4w
We move all terms to the left:
5w-51.25-(13+3/4w)=0
Domain of the equation: 4w)!=0We add all the numbers together, and all the variables
w!=0/1
w!=0
w∈R
5w-(3/4w+13)-51.25=0
We get rid of parentheses
5w-3/4w-13-51.25=0
We multiply all the terms by the denominator
5w*4w-13*4w-(51.25)*4w-3=0
We multiply parentheses
5w*4w-13*4w-205w-3=0
Wy multiply elements
20w^2-52w-205w-3=0
We add all the numbers together, and all the variables
20w^2-257w-3=0
a = 20; b = -257; c = -3;
Δ = b2-4ac
Δ = -2572-4·20·(-3)
Δ = 66289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-257)-\sqrt{66289}}{2*20}=\frac{257-\sqrt{66289}}{40} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-257)+\sqrt{66289}}{2*20}=\frac{257+\sqrt{66289}}{40} $
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